1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Algebra 2, solve with steps

  1. Sep 25, 2014 #1
    1. The problem statement, all variables and given/known data

    a1b1/x1= a2b2/x2


    solve for x2

    2. Relevant equations

    no relevant questions apply, this is a stand alone review question

    3. The attempt at a solution

    multiply times reciprocal to get rid of denominator on left

    (x1) (a1b1/x1)= (a2b2/x2)(x1)

    a1b1 = (a2b2x1/x2)

    multiply times reciprocal to get rid of denominator on right

    (x2) a1b1/x1= a2b2x1/x2 (x2)

    a1b1x2 = a2b2x1

    divide by a1b1 to get x2 alone

    a1b1x2/a1b1 = a2a2x1/(a1b1)

    x2 = a2b2x1/(a1b1)


    I know I have missed something, but this is my best attempt at solving this problem. Could someone please review and help me figure out what I missed?
     
    Last edited: Sep 25, 2014
  2. jcsd
  3. Sep 25, 2014 #2

    Ray Vickson

    User Avatar
    Science Advisor
    Homework Helper

    You have not missed anything; your answer is correct (provided that you never divide by zero anywhere, so provided that all x's a's and b's are nonzero). Your argument is very long-winded, though, and can be shortened into two lines:
    [tex] \frac{a_1 b_1}{x_1} = \frac{a_2 b_2}{x_2}\, ,\\
    \text{so }\; \frac{x_1}{a_1 b_1} = \frac{x_2}{a_2 b_2} \, ,\\
    \text{so }\; x_2 = \frac{x_1}{a_1 b_1} a_2 b_2 = \frac{a_2 b_2 x_1}{a_1 b_1} [/tex]
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Algebra 2, solve with steps
  1. Solve algebraically (Replies: 2)

  2. Algebra 2 (Replies: 2)

Loading...