# Algebra 2, solve with steps

iamjon.smith

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a1b1/x1= a2b2/x2

solve for x2

## Homework Equations

no relevant questions apply, this is a stand alone review question

## The Attempt at a Solution

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multiply times reciprocal to get rid of denominator on left

(x1) (a1b1/x1)= (a2b2/x2)(x1)

a1b1 = (a2b2x1/x2)

multiply times reciprocal to get rid of denominator on right

(x2) a1b1/x1= a2b2x1/x2 (x2)

a1b1x2 = a2b2x1

divide by a1b1 to get x2 alone

a1b1x2/a1b1 = a2a2x1/(a1b1)

x2 = a2b2x1/(a1b1)

I know I have missed something, but this is my best attempt at solving this problem. Could someone please review and help me figure out what I missed?

Last edited:

$$\frac{a_1 b_1}{x_1} = \frac{a_2 b_2}{x_2}\, ,\\ \text{so }\; \frac{x_1}{a_1 b_1} = \frac{x_2}{a_2 b_2} \, ,\\ \text{so }\; x_2 = \frac{x_1}{a_1 b_1} a_2 b_2 = \frac{a_2 b_2 x_1}{a_1 b_1}$$