Algebra Question: Finding Distance When a Train and Car Meet

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To find the distance when the car catches the train, the car starts 100 miles behind the train, which is traveling at 50 MPH while the car travels at 70 MPH. The car closes the gap at 20 MPH (70 - 50). To calculate the time it takes for the car to catch the train, divide the distance (100 miles) by the speed difference (20 MPH), resulting in 5 hours. The distance the car travels in that time is 70 MPH multiplied by 5 hours, equaling 350 miles. The initial calculations mistakenly solved for time instead of distance, which led to an incorrect answer.
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Train leaves station going 50MPH
Car leaves station going 70MPH - 2 hours later

How far til car catches train?

This should be so simple, here is what I've done:

d=50t
d=70(t-2)

50t=70(t-2)
50t=70t-140
140=20t

I get t=7 miles for my final answer, but according to the book this is wrong. Why?
 
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try it this way: when the car starts the train is 100 miles away. the car makes up ground at 20 miles/hour (70-50)... how many hours does it take to catch the train... how many miles did the car go in that time.
 
How did you get miles from that? If
d=50mph*t hours
d=70mph*(t-2)hours

50mph*t hours=70mph*(t-2)hours
50mph*t hours=70mph*t hours-140 miles
140 miles=20mph*t hours
140miles/20mph = t hours
7 hours = t hours
 
I think the problem is that you've solved for t when the question asks you to solve for d, the distance.

Of course you can now just put t back into one of the equations.
 
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