Algebraic Geometry - D&F Section 15.1, Exercise 24

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Dummit and Foote Section 15.1, Exercise 24 reads as follows:

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Let V = \mathcal{Z} (xy - z) \subseteq \mathbb{A}^3.

Prove that V is isomorphic to \mathbb{A}^2

and provide an explicit isomorphism \phi and associated k-algebra isomorphism \widetilde{\phi} from k[V] to k[ \mathbb{A}^2] along with their inverses.

Is V = \mathcal{Z} (xy - z^2) isomorphic to \mathbb{A}^2?

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I would appreciate some help and guidance with getting started with this exercise [I suspect I might need considerable guidance! :-( ]Some of the background and definitions are given in the attachment.Peter
 

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So you you need to find an isomorphism between ##\mathbb{A}^2## and the surface ##z=xy##. A suitable isomorphism should be ##\varphi(x,y) = (x,y,xy)##. Does that help?
 
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Thanks for the help, R136a1

Will now reflect on your guidance

Peter
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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