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i can take this down to
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Algebreic expression
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i can take this down to
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- #2
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So you are trying to simplify the expression, I take it?
[tex]{(\sqrt{a} + 1)^2 - {a-\sqrt {ax} \over \sqrt a - \sqrt x} \over (\sqrt a + 1)^3 - a \sqrt a + 2} [/tex]
= [tex]{(a + 2 \sqrt a + 1)(\sqrt a - \sqrt x) - (a - \sqrt {ax}) \over (\sqrt a - \sqrt x)((\sqrt a + 1)^3 - a \sqrt a + 2)} [/tex]
= [tex]{a \sqrt a - a \sqrt x +2a - 2 \sqrt a \sqrt x + \sqrt a - \sqrt x - a + \sqrt{ax} \over (\sqrt a - \sqrt x)(a^{3 \over 2} + 3a + 3 \sqrt a + 1 - a^{3 \over 2} + 2)} [/tex]
And then we group like terms and can cancel some things out
=[tex] {a \sqrt a + a + \sqrt a - a \sqrt x - \sqrt{ax} - \sqrt x \over 3(a \sqrt a + a + \sqrt a - a \sqrt x - \sqrt a \sqrt x - \sqrt x} [/tex]
= [tex] {1 \over 3} [/tex]
[tex]{(\sqrt{a} + 1)^2 - {a-\sqrt {ax} \over \sqrt a - \sqrt x} \over (\sqrt a + 1)^3 - a \sqrt a + 2} [/tex]
= [tex]{(a + 2 \sqrt a + 1)(\sqrt a - \sqrt x) - (a - \sqrt {ax}) \over (\sqrt a - \sqrt x)((\sqrt a + 1)^3 - a \sqrt a + 2)} [/tex]
= [tex]{a \sqrt a - a \sqrt x +2a - 2 \sqrt a \sqrt x + \sqrt a - \sqrt x - a + \sqrt{ax} \over (\sqrt a - \sqrt x)(a^{3 \over 2} + 3a + 3 \sqrt a + 1 - a^{3 \over 2} + 2)} [/tex]
And then we group like terms and can cancel some things out
=[tex] {a \sqrt a + a + \sqrt a - a \sqrt x - \sqrt{ax} - \sqrt x \over 3(a \sqrt a + a + \sqrt a - a \sqrt x - \sqrt a \sqrt x - \sqrt x} [/tex]
= [tex] {1 \over 3} [/tex]
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