Alkene Products: Understanding the Possibilities in E2 Elimination Reactions

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In E2 elimination reactions, multiple alkene products can form due to the creation of a double bond at different locations on the molecule. Each alkene can exhibit stereoisomerism, resulting in E and Z configurations. While an initial expectation might suggest four products, the correct total is five. The additional product arises from a unique configuration or position of the double bond that was not initially considered. Understanding these possibilities is crucial for accurately predicting reaction outcomes in organic chemistry.
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How man different alkene-products, including stereoisomers, are possible when this molecule reacts in an E2 elimination reaction?

What will happen here is that I leaves the molecule, while a new double bond is created. The new bond can be created on two places, so that we have two different alkenes. We also have two stereoisomers (E and Z) for each of these solutions. I expect the answer to be 4.

However, the correct answer is 5. What's the last product?
 
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leopard said:
The new bond can be created on two places

I was never an organiker, but logic tells me that's not true.
 
Ditto.
 
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
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