Am i correct in getting a low value?

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The discussion revolves around calculating the fuel cost of raising a 103 kg beam using a crane, which consumes fuel that loses 1 MJ of energy, with 85% lost to heating the air. The internal energy of the crane's engine increases by 4.0×10^4 J, while the gravitational potential energy of the crane's superstructure and the beam increases by 10^4 J. Participants are encouraged to share their calculations and identify where they are struggling with energy conservation laws. The emphasis is on understanding the energy transfer involved in the process and finding the correct approach to determine the fuel cost. The conversation highlights the challenges faced in applying theoretical principles to practical problems.
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A crane uses its petrol engine to lift a beam of mass 103 kg by height
h. The fuel burned loses 1 MJ (106 J) of chemical potential energy, 85%
of this being transferred by heating to the air. The internal energy of the
crane’s engine increases by 4.0×104 J, while that of the crane’s superstructure
and the beam is unchanged. The crane’s superstructure (not engine or fuel)
increases in gravitational potential energy by 104 J. Everything is at rest
before and after. Assume all transfer by working out of the crane is used to
lift the beam.
(a) [10 marks] The calorific value of the fuel is 43 MJ kg−1, its density is 737
kg m−3 and it costs 90p per litre (there are 1000 litres in 1 m3). What was
the fuel cost of raising the beam?
 
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I tried to apply lots of the basic energy conservations laws but get stuck when approaching an answer making me very depressed. Sympathy work well on here?
 
Lets see your working so far and where you are are stuck.
 
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