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Am I to the end of this Boolean Algebra Problem?

  1. Jul 19, 2006 #1
    Here's the problem:

    a'b'c'd' + a'b'cd' + a'b'cd + ab'c'd' + abc'd'

    I've gotten it down to:
    ac'd' + b'c'd' + a'b'c

    Having trouble coming up with a way to simplify it more...Is this as far as it can go?
    Any help appreciated, thanks...
  2. jcsd
  3. Jul 19, 2006 #2


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    Staff: Mentor

    I did a quick K-map, and got it down to 3 terms, but my terms are different from yours. I got 2 3-terms and one 4-term.

    Did you use a Karnaugh map? Where did the ac'd' term come from, for example?
  4. Jul 19, 2006 #3
    I used Boolean Algebra Axioms that I had learned in college to simplify it to the result that I got...

    The lines are on the board at work, I'll try to update this thread with them tomorrow from work...

    Thanks for the response...
  5. Jul 20, 2006 #4


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    Staff: Mentor

    I found an error in my quick K-map. I now get the same answer as you. For problems like this with up to 4 inputs, the K-map is the easiest way to see what the simplest answer is. Well, assuming you don't make an error like I did yesterday :blushing:
  6. Jul 20, 2006 #5
    no problem...it happens...thanks for the update...i feel confident about the math, i just wanted it smaller to help out in a query that i was writing...
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