a .25kg block oscillates on the end of a spring with a spring constant of 200N/m. If the oscillation is started by elongating spring to 0.15m and giving the block a speed of 3.0m/s. The amplitude is?
omega= sqrt(k/m), Vm = (omega)Xm
The Attempt at a Solution
omega= sqrt (200/.25) = 28.28 (3m/s) = 28.28Xm (3/28.28) = .106
The correct answer is .18m..what am i missing?