Amplitude of string when the string breaks

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    Amplitude String
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The discussion centers on the amplitude of oscillation when a string breaks, particularly in relation to the mass of the oscillating system. Participants debate whether the amplitude increases or decreases after the mass is removed, with one side arguing that the new equilibrium position is higher, thus increasing amplitude. However, there is confusion regarding the implications of this change, with some asserting that the extreme position does not necessarily increase the amplitude. Clarification is sought on why the assertion about amplitude not increasing is considered incorrect. The conversation highlights the complexities of oscillation dynamics in relation to mass and equilibrium.
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Homework Statement



my question is on part b

Homework Equations





The Attempt at a Solution



the period will be shorter due to smaller mass of oscillating system... but the amplitude is greater( ans from my book , in my opinion, the amplitude should be smaller because the string is (dispalcement) is displaced lesser if the mass is removed
 

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By the time the string breaks the metal strip is already deflected downwards to its maximum deflection so your reasoning makes no sense. The strip will oscillate around the new equilibrium position which is further up since the mass is removed. That means the extreme position is further away from the equilibrium position increasing the amplitude.
 
dauto said:
By the time the string breaks the metal strip is already deflected downwards to its maximum deflection so your reasoning makes no sense.
:smile:

The strip will oscillate around the new equilibrium position which is further up since the mass is removed.
True.

That means the extreme position is further away from the equilibrium position increasing the amplitude.
Not true.
 
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NascentOxygen said:
:smile:


True.


Not true.
why the third statement is not true? i can't unbderstand
 
Someone reply?
 
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