Convert LNA 433MHz Signal (21dB) to DC Voltage - Ryan's Question

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To convert a 433MHz LNA signal (21dB) to a lower frequency, a mixer circuit is recommended. For converting a 50MHz sine wave signal to a proportional DC voltage, a detector diode is suggested. These components will help achieve the desired signal processing. The discussion focuses on practical circuit solutions for signal frequency reduction and amplitude-to-DC conversion. Understanding these components is crucial for effective signal manipulation in RF applications.
RLovelett
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My scenario:
LNA 433MHz signal (21dB) from antenna and the difference between the two signals with a 4.1dB gain. I would like to take the result of the difference amplifier an produce a DC value that is proportional to the output.

Question 1:
What type of circuit would lower the frequency to something like 50MHz?

Question 2:
What type of circuit would take the amplitude of a 50MHz sine wave signal and convert it to a DC voltage that is proportional?

Many thanks!
Ryan
 
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Answer 1:
A mixer

Answer 2:
A detector diode.
 

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