can anyone explain the behaviour of this function? i looked at the graph and everything, but if i solve it one way i get a different answer than if i solve it another way.(adsbygoogle = window.adsbygoogle || []).push({});

Ln[(x+1)^2]=2

one way to solve it (What i did)

e^{Ln[(x+1)^2]}=e^2

(x+1)^2=e^2

(x+1)^2-e^2=0

(x+1-e)(x+1+e)=0

x=e-1 and x=-e-1

another way, what my math teacher did

Ln[(x+1)^2]=2

2Ln(x+1)=2

Ln(x+1)=1

X+1=e^1

x=e-1

as you can see somehow one of his roots, the -e-1 is just...gone. i checked the math 1 million times. this is puzzling me for a few months now...where did the root go? i never asked him becasue he's knida cranky...but can you help me plz?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# An interesting equation.

**Physics Forums | Science Articles, Homework Help, Discussion**