Analysis of Functions I: increase, decrease, and concavity

Click For Summary

Homework Help Overview

The discussion revolves around analyzing functions to determine intervals of increase, decrease, concavity, and inflection points. The specific functions under consideration include polynomial and logarithmic expressions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore how to find intervals of increase and decrease by setting first derivatives to zero. They also discuss the process of finding concavity and inflection points using second derivatives.

Discussion Status

Some participants provide guidance on solving equations related to the second derivative and suggest methods for finding critical points. There is a mix of attempts to clarify the steps needed to analyze the functions, with some participants expressing confusion about specific calculations.

Contextual Notes

Participants mention the need for proper notation and the importance of understanding fundamental calculus concepts, indicating a potential gap in foundational knowledge. There is also a request for clarification on how to handle fractions and derivatives in the context of the problems presented.

josh_123
Messages
15
Reaction score
0
Hello I need help with these problems. The direction said

a. find the intervals on which f is increasing, b. the intervals on which f is decreasing, c. the open intervals on which f is concave up, d. the open intervals on which f is concave down and e. the x-cordincates of all inflection points
1. f(x)=x^4-8x^2+16
I find a,b c and d for this function. However I have trouble finding the inflection points for this function. When you find the inflection point you suppose to set up the second derivative of the function to equal 0 but I have no idea how to solve it afterward. Is there an inflection point for this equation?
f"(x)=12x^2-16
2. f(x)=x/(x^2+2)
so f'(x)=-x2+2/(x2+2)2
to find a,b I have to set this equal to 0 and solve it. How do I solve it? and what would be the second derivative and how do I solve it by setting it up to equal to 0 to know if it's concave up or down?
3. f(x)=x2lnx
The first derivative is 2xlnx+x. How do I solve it or know what is a, b is?and the second derivative is 2lnx+3. How do I use the second derivative to solve for c,d and e?

Please help! Thank you!
 
Physics news on Phys.org
josh_123 said:
1. f(x)=x^4-8x^2+16
I find a,b c and d for this function. However I have trouble finding the inflection points for this function. When you find the inflection point you suppose to set up the second derivative of the function to equal 0 but I have no idea how to solve it afterward. Is there an inflection point for this equation?
f"(x)=12x^2-16

So you need to solve the equation 12x^2-16 = 0. What is your problem?

josh_123 said:
2. f(x)=x/(x^2+2)
so f'(x)=-x2+2/(x2+2)2
to find a,b I have to set this equal to 0 and solve it. How do I solve it? and what would be the second derivative and how do I solve it by setting it up to equal to 0 to know if it's concave up or down?

Use parentheses. The formula is wrong without them.
You will have a fraction. It can be zero if the nominator is zero.

josh_123 said:
3. f(x)=x2lnx
The first derivative is 2xlnx+x. How do I solve it or know what is a, b is?and the second derivative is 2lnx+3. How do I use the second derivative to solve for c,d and e?

To find x where the derivative is zero, factor out x.

ehild
 
josh_123 said:
Hello I need help with these problems. The direction said

a. find the intervals on which f is increasing, b. the intervals on which f is decreasing, c. the open intervals on which f is concave up, d. the open intervals on which f is concave down and e. the x-cordincates of all inflection points
1. f(x)=x^4-8x^2+16
I find a,b c and d for this function. However I have trouble finding the inflection points for this function. When you find the inflection point you suppose to set up the second derivative of the function to equal 0 but I have no idea how to solve it afterward. Is there an inflection point for this equation?
f"(x)=12x^2-16
What? You don't know how to solve 12x^2- 16= 0? Add 16 to both sides, divide both sides by 12, then take the square root of both sides.

2. f(x)=x/(x^2+2)
so f'(x)=-x2+2/(x2+2)2
to find a,b I have to set this equal to 0 and solve it. How do I solve it?
you are taking Calculus and do not know how to solve equations like this? Multiply both sides of the equation by that denominator to get 2- x^2= 0

and what would be the second derivative and how do I solve it by setting it up to equal to 0 to know if it's concave up or down?
Differentiate it, using the quotient rule again.

3. f(x)=x2lnx
The first derivative is 2xlnx+x. How do I solve it or know what is a, b is?
Oh, c'mon! 2xln(x)+ x= x(2ln(x)+ 1)= 0. One thing you surely learned long ago is that a product is equal to 0 only if one or more of the factors is 0. So here, either x= 0 or 2ln(x)+ 1= 0: x= 0 or ln(x)= -1/2.

and the second derivative is 2lnx+3. How do I use the second derivative to solve for c,d and e?
2ln(x)+ 3= 0 leads to ln(x)=-3/2. Again, you should have learned in algebra or precalculus that if ln(x)= a then x= e^a. Once you know where it zero, you can determine the intervals in which the second derivative is positive or negative.

Please help! Thank you!
 
Actually I finished this before checking back haha. Please delete this post
 
Last edited:

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
11
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K