Analyzing (1+z^3)/(-1+z) using Cauchy-Riemann Equations

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This isn't my whole question, just part of the question I am trying to do to show the whole thing is analytic.

I can do the rest but showing this is analytic:

(1+z^3)/(-1+z)

Is trickey for me..

I am trying to show it is analytic by showing it satisfies the cauchy riemann equations.

I take z = x + iy

And my function turns into (after simplifying)

[x^3 - 3xy^2 + 1 + i(3yx^2 - y^3)] / (x + iy -1)

Now I can split the numerator in real and imaginary parts, but the denominator has an i in it which is in the way for me, hence I can't split the whole thing into real and imaginary parts. So I can't show it satisfies the CRE.

Anyone know, or should I not be using the CRE?

Thanks
 
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Try multiplying the numerator and denominator of your expression by the complex conjugate of the denominator (that is, x-1-i y). What happens?
 
PingPong said:
Try multiplying the numerator and denominator of your expression by the complex conjugate of the denominator (that is, x-1-i y). What happens?

Ah thanks :)



1. Homework Statement

Determine the largest subset of C (complex numbers) on which the following function is analytic, and compute its derivative.

2. Homework Equations

exp[(z^3+1)/(z-1)]


I'm trying to compute it's derivative right now, but how would I find its largest subset?
 
Firepanda said:
1. Homework Statement

Determine the largest subset of C (complex numbers) on which the following function is analytic, and compute its derivative.

2. Homework Equations

exp[(z^3+1)/(z-1)]


I'm trying to compute it's derivative right now, but how would I find its largest subset?

First find where the function is not analytic.

The same question was posed at https://www.physicsforums.com/showthread.php?t=278123
 
Apparantly it can be don't the same way as with real numbers, but I don't know how to do that either lol..
 
bump before bed
 
The only point in question is z=1. The best outcome there would be that it's a removable singularity. It's not. Can you show that it's not?
 
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