Analyzing Forces on a Block: A Scientific Approach

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The discussion focuses on analyzing the forces acting on a block with a mass of 22 kg, being pulled with a force of 290 N at a 35-degree angle. Key calculations include determining the net force, which is zero due to constant velocity, and the components of tension and gravitational forces. The tension's x-component is calculated as 237.55 N, while the y-component is 166.34 N, matching the gravitational force of 215.6 N. The friction force cannot be calculated without the coefficient of friction (μ), leading to further inquiries about how to determine it. Overall, the analysis emphasizes balancing forces in both horizontal and vertical directions to achieve equilibrium.
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Homework Statement



1) What is the net force on the block? (Cartesian Coordinate system)
2) What is the X component of the tension force on the block
3) What is the x-component of the force exerted by the floor on the block (the friction force)?
4) What is the y-component of the force exerted by the rope on the block?
5) What is the y-component of the force exerted by the Earth on the block?
6) What is the y-component of the force exerted by the floor on the block (sometimes called the "normal" force, because it is perpendicular to the floor)?

I pull on the rope with the force of 290 N
Mass of block is 22kg
Block moves at constant 1.3m/s
Angle of 35 degrees with the floor.

Homework Equations


p=mv
\Deltap=fnet\Deltat
ma = T - W
Ff = \muN

The Attempt at a Solution


1) The net force will be the total force acting on the block, therefore in the X direction it would include the X component of the force I exert, and the Y component of the force I exert minus the force of gravity acting on the object.
Fx, me = 290 N * cos(35) = 237.55
Fy, me = 290 N * sin(35) = 166.34
Fgravity = mg = 215.6
Therefore <237.55, (166.34-215.6), 0>

2) Velocity is constant, so no acceleration, therefore T = W. Therefore, I don't know where to go with this.

3) I do not know mu, don't know how to solve for the force of friction.

4) Would this be equal to the force I exert on the rope multiplied by the sin of 35?
290sin(35) = 166.34

5) Already calculated this as well, Fg = mg = 215.6

6) Equal and opposite of Fg?

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
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For question 1
What is the acceleration of the block?
How is the acceleration of the block related to the net force acting on it?

Once you get the answer to question 1 sorted out the rest should be easier to handle.

Clarification
Your problem statement does not give the mass of the block. What is it?
 
For question 1) Thanks! Of course, the net force is going to be 0 if there is no acceleration.

For mass of object, had a typo, what was originally mass of rope should be mass of block (22kg) the mass of rope/myself is supposed to be negligible, i apologize.

Figured out 2.

For 3, how do I calculate Ff without knowing \mu?

Figured out 4 & 5

For 6, is it the sum of Earth + rope forces, multiplied by 1 (since its opposite direction)?
 
Nal101 said:
For question 1) Thanks! Of course, the net force is going to be 0 if there is no acceleration.

For mass of object, had a typo, what was originally mass of rope should be mass of block (22kg) the mass of rope/myself is supposed to be negligible, i apologize.

Figured out 2.

For 3, how do I calculate Ff without knowing \mu?

The sum of the horizontal components of the net force must be zero. Just balance the forces. "To the right" is positive, "to the left" is negative.

Figured out 4 & 5

For 6, is it the sum of Earth + rope forces, multiplied by 1 (since its opposite direction)?
The sum of the vertical components of the net force must be zero. "Up" is positive, "down" is negative.
 
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