Analyzing Parallel RC Circuits with Time Constant Variation

AI Thread Summary
To analyze the time constant of a parallel RC circuit when the switch is on, one must derive a differential equation using Kirchhoff's laws to determine the charge on the capacitor. The time constant can be identified within this equation. A recommended approach is to find the Thevenin equivalent sources for the circuit when the switch is open and closed, simplifying the analysis into two distinct RC circuits. Understanding the charging equation is crucial for calculating the capacitor's potential at a specific time, such as t=2s. This method provides clarity on the behavior of the circuit under varying conditions.
VHAHAHA
Messages
58
Reaction score
0
the attached file is the question

I know the time constant after opening the switch

but how can i know the time constant when the switch is on?

This is NOT the classic initial and AFTER A LONG LONG LONG Time question

How can i know the potential of C in t=2s ?

What is the equation for charging ?

Plz help, i googled for a long time but still can't get the ans
 
Last edited by a moderator:
Physics news on Phys.org
What is the equation for charging ?
With Kirchhoff's laws, you can get a differential equation for the charge of the capacitor. The time constant can be seen in this equation.
 
One approach would be to find the Thevenin equivalent sources that the capacitor "sees" when the switch is open and when the switch is closed. That'll give you two simple RC circuits to work with...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top