Analyzing Torque and Angular Acceleration in a Flywheel Problem

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Homework Help Overview

The problem involves analyzing the angular acceleration of a flywheel, which is modeled as a uniform disk. The disk has a specified diameter and weight, and the question pertains to the angular acceleration resulting from a net torque, as well as the torque required to stop the disk from a given rotational speed.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of angular acceleration using torque and moment of inertia, with one participant expressing confusion over differing results from their teacher's solution. Questions arise regarding the interpretation of 'net force' versus 'net torque' and the correct use of units.

Discussion Status

The discussion is ongoing, with participants exploring the definitions and implications of torque and force in the context of the problem. Some guidance has been offered regarding unit interpretation, and there is recognition of potential typographical errors in the problem statement.

Contextual Notes

Participants note the importance of distinguishing between force and torque based on the units provided, as well as the potential for confusion stemming from the use of English units.

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1. Homework Statement
A flywheel in the form of a uniform disk (I = ½ MR2) 5.0 ft in diameter, weighs 650 lb. What will be its angular acceleration if a net force of 225 ft-lb acts it upon? If the disk is rotating at 1200 rev/min, what torque is required to stop it in 30 minutes?

Homework Equations



T=I\alpha=Fr

The Attempt at a Solution



I need help in the first question, because apparently I arrive with a different answer from the solution that my teacher gave me. I just wanted to know if I got it wrong or my teacher forgot something

So using the definition of torque, I solve for alpha which is

alpha = FR/I

Defining I in the equation gives

alpha = FR/(1/2)MR2

Since the given is weight, I still have to define mass in the equation

alpha = FR/(1/2)(W/g)R2

Substituting the values, I'll have

alpha = (225)(2.5)/(1/2)(650/9.8)(2.5)2
alpha = 2.71 rad/s2

The solution in my note was

alpha = 2g(Torque)/WR2

which results to 3.54rad/s2Am I missing something? Or is everything just right?
 
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XwyhyX said:
alpha = FR/(1/2)(W/g)R2

Substituting the values, I'll have

alpha = (225)(2.5)/(1/2)(650/9.8)(2.5)2
alpha = 2.71 rad/s2
Two problems:
(1) Even though it says 'net force', what's really given is the net torque.
(2) Careful with units: g ≠ 9.8
 
Oh I see, one question though, How can I tell whether its net force or net torque?
 
XwyhyX said:
Oh I see, one question though, How can I tell whether its net force or net torque?
The units given (ft-lb) are for torque, not force. Check the problem statement; I suspect there was a typo somewhere.
 
Thanks! I got my english units rambled up, I usually think of pounds as mass, so I was thinking of what the english unit is for force. Nevermind, I understand it now. :D
 

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