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Using R=v^2sin2x/g how do you prove that the angle of 45 yields the maximum distance?

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- Thread starter tharindu
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- #1

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Using R=v^2sin2x/g how do you prove that the angle of 45 yields the maximum distance?

- #2

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then you will have sin(2theta) = 1 >> 2theta = arcsin(1) >> 2theta= 90 >> theta = 45 ..

hopefully that was clear .. :)

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