Angle of Incline Calculation with Coefficient of Friction

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Homework Help Overview

The problem involves calculating the angle of an inclined plane given the weight of a body, the force required to pull it up the incline, and the coefficient of friction. The context is rooted in physics, specifically in the study of forces on inclined planes and friction.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the body, including weight and friction. There are inquiries about the angle at which the force is applied and the relationship between the perpendicular weight component and the frictional force.

Discussion Status

The discussion is ongoing, with participants providing insights into the forces involved and questioning the assumptions made about the angle and force components. Some guidance has been offered regarding the relationship between the weight and the frictional force, but no consensus has been reached on a specific method to find the angle.

Contextual Notes

Participants are working with specific values for weight, applied force, and coefficient of friction, but there may be some confusion regarding the application of these values in the context of the problem.

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Hey would someone mind taking a crack at this one? I know the final answer is 28.73, however I can't figure out the equation to get it.

On a certain inclined plane, a body weighs 50N and requires a force of 35N to pull it up the incline. If the coefficient of friction is 0.25, find the angle of the incline.
 
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Why don't you take a crack at it?

Call the angle θ and analyze the forces acting on the body as it is pulled up the incline.
 
at what angle is the force being applied?
 
well, first you need to remember that the weight (50N) is directed downwards, but the force of friction needs the weight applied PERPENDICULAR to the surface. Find this, then you will get your angle.
 
Aeroneer said:
well, first you need to remember that the weight (50N) is directed downwards, but the force of friction needs the weight applied PERPENDICULAR to the surface. Find this, then you will get your angle.

parallel
 
Mu naught said:
parallel

no. you must have misunderstood.
I meant the angle perp. multiplied by the coeff. of friction will give u your force countering the 35N (which is assumed to be equal). so fill in the blanks to find the angle.
 

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