1. The problem statement, all variables and given/known data An archerfish hunts by dislodging an unsuspecting insect from its resting place with a stream of water expelled from the fish's mouth. Suppose the archerfish squirts water with a speed of 2.00 m/s at an angle of 50 degrees above the horizontal, and aims for a beetle on a leaf 3.00 cm above the water's surface. a. Find the time it takes for the water to hit the beetle; why are there 2 answers? b. At what horizontal distance from the beetle should the archerfish fire if it is to hit its target in the least time? c. Find the angle (above the horizontal) of the archerfish's line of sight; explain why the line of sight angle is not 50 degrees! What I want to know is if the line of sight angle is allowed to be greater than the angle of the squirt? 2. Relevant equations 3 DVAT formulas 3. The attempt at a solution After I solved for t (using quadratic formula, vertical acceleration, initial vertical velocity(which I got using law of sines), and delta y), I solved for delta x using the smaller of the two values I got for t (this time is when it reaches .03m high before the peak of the curve). The value I got for delta x was .023 m. I am 95% certain that this a correct value. Then to solve for the angle of the line of sight of the archerfish I used delta x, delta y, and law of tangents and got an angle of 52 degrees above the horizontal. However, the angle of the squirt of water was 50 degrees above the horizontal, and I am unsure if the angle of the line of sight is allowed to be larger than the angle of the squirt of water?