Angle of particles after elastic collision

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SUMMARY

The discussion focuses on the elastic collision between two particles, specifically analyzing the scenario where a particle of mass M1 collides with a stationary particle of mass M2. It is established that if M1 is greater than M2, the angle of M1 after the collision cannot exceed arcsin(M2/M1). The velocities after the collision are derived as v1`=v1*[(M1-M2)/(M1+M2)] and v2`=v1*[(2M1)/(M1+M2)], which are crucial for determining the maximum angle of deflection for M1.

PREREQUISITES
  • Understanding of elastic collisions in physics
  • Knowledge of conservation of momentum and kinetic energy principles
  • Familiarity with trigonometric functions, specifically arcsin
  • Basic algebra for manipulating equations
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  • Study the derivation of angles in elastic collisions using vector projections
  • Explore advanced topics in momentum conservation in multi-particle systems
  • Learn about the implications of mass ratios in collision outcomes
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators seeking to explain the principles of elastic collisions and their mathematical implications.

ajl1989
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Homework Statement


A particle of mass M1 collides elastically with a particle of mass M2 at rest. Show that if M1>M2 then the angle of M1 after the collision cannot exceed the value arcsin(M2/M1).


Homework Equations


conservation of momentum: M1v1=M1v1`+M2v2`
conservation of kinetic energy: (1/2)M1v12=(1/2)M1v1`2+(1/2)M2v2`2


The Attempt at a Solution


I've figured out that the velocities after collision are:
v1`=v1*[(M1-M2)/(M1+M2)]
and
v2`=v1*[(2M1)/(M1+M2)]
but I don't know how to find the maximum angle of M1 after collision. Please help
 
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ajl1989 said:

Homework Statement


A particle of mass M1 collides elastically with a particle of mass M2 at rest. Show that if M1>M2 then the angle of M1 after the collision cannot exceed the value arcsin(M2/M1).

Homework Equations


conservation of momentum: M1v1=M1v1`+M2v2`
conservation of kinetic energy: (1/2)M1v12=(1/2)M1v1`2+(1/2)M2v2`2

The Attempt at a Solution


I've figured out that the velocities after collision are:
v1`=v1*[(M1-M2)/(M1+M2)]
and
v2`=v1*[(2M1)/(M1+M2)]
but I don't know how to find the maximum angle of M1 after collision. Please help

what's the critical point between when M1 > M2 is true, and when it's no longer true?

what will M1 - M2 be at that point?

to get angle into your equation, think projection.
 

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