Angle on ramp with cart and weights on rope at end

Click For Summary
SUMMARY

The discussion focuses on analyzing the forces acting on a cart on a frictionless ramp with weights suspended by a rope. Key variables include the normal force (ny), gravitational forces (F_G)_x and (F_G)_y, and the angle theta. Participants emphasize the importance of correctly applying trigonometric functions and defining positive directions for variables. The gravitational constant is specified as 9.8 m/s², and the necessity of consistent sign conventions is highlighted.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with trigonometric functions in physics
  • Knowledge of force diagrams and free-body diagrams
  • Basic principles of mechanics involving frictionless surfaces
NEXT STEPS
  • Review the application of trigonometric functions in physics problems
  • Study the concept of free-body diagrams for complex systems
  • Learn about the implications of sign conventions in physics
  • Explore the dynamics of systems with multiple forces acting simultaneously
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and anyone involved in teaching or learning about forces and motion on inclined planes.

jskrzypi
Messages
5
Reaction score
2
Homework Statement
A 250g cart with 250g of weight is on a ramp. Rope attached to right side going over pulley with a 50g weight on end. Calculate angle ramp needs to be at to maintain cart stationary

edit: track is frictionless
Relevant Equations
Fnetx=nx+Tx+(FG)x=0
Fnety=ny+Ty+(FG)y=0
I believe the nx, Ty, and (fs)y are all 0. I could solve for theta if I could figure out (fs)x or ny.

edit: Track is frictionless, so delete (fs) forces.

IMG_20210329_210038.jpg
 
Last edited:
Physics news on Phys.org
You wrote ##(F_G)_x## as ##Mg\cos\theta## and ##(F_G)_y## as ##Mg\sin\theta##. Check your trig functions here. Also, shouldn't ##(F_G)_x## and ##(F_G)_y## both be negative?
 
I just caught the cos/sin issue. And I wasn't sure about them being negative. Obviously they are, but I may be getting it confused. Class said g is just a scalar of 9.8 m/s^2, and we need to add in the signs so it would be +(-g). I just don't know when/where to add the negatives.
 
jskrzypi said:
don't know when/where to add the negatives.
First, you need to define which way you are taking as positive for each variable. It doesn’t matter what you choose as long as you are consistent.
I would take positive as downslope for the cart and vertically down for the suspended mass.
 

Similar threads

Replies
18
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
46
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 40 ·
2
Replies
40
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K