Angle on ramp with cart and weights on rope at end

AI Thread Summary
The discussion revolves around solving for the angle theta in a frictionless scenario involving a cart and weights on a rope. The initial belief is that the normal forces (nx, Ty, and (fs)y) are zero, but the user is unsure about the correct application of trigonometric functions for gravitational forces. There is confusion regarding the signs of the forces, particularly whether (F_G)_x and (F_G)_y should be negative. A suggestion is made to define a consistent positive direction for the variables, with downslope for the cart and vertically down for the suspended mass. Clarifying these points is essential for accurately solving the problem.
jskrzypi
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Homework Statement
A 250g cart with 250g of weight is on a ramp. Rope attached to right side going over pulley with a 50g weight on end. Calculate angle ramp needs to be at to maintain cart stationary

edit: track is frictionless
Relevant Equations
Fnetx=nx+Tx+(FG)x=0
Fnety=ny+Ty+(FG)y=0
I believe the nx, Ty, and (fs)y are all 0. I could solve for theta if I could figure out (fs)x or ny.

edit: Track is frictionless, so delete (fs) forces.

IMG_20210329_210038.jpg
 
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You wrote ##(F_G)_x## as ##Mg\cos\theta## and ##(F_G)_y## as ##Mg\sin\theta##. Check your trig functions here. Also, shouldn't ##(F_G)_x## and ##(F_G)_y## both be negative?
 
I just caught the cos/sin issue. And I wasn't sure about them being negative. Obviously they are, but I may be getting it confused. Class said g is just a scalar of 9.8 m/s^2, and we need to add in the signs so it would be +(-g). I just don't know when/where to add the negatives.
 
jskrzypi said:
don't know when/where to add the negatives.
First, you need to define which way you are taking as positive for each variable. It doesn’t matter what you choose as long as you are consistent.
I would take positive as downslope for the cart and vertically down for the suspended mass.
 
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