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Jar9284
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Homework Statement
You switch a food blender from its high to its low setting; the blade speed drops from 3100 rpm to 1300 rpm in 2.1 s. How many revolutions does it make during this time?
Homework Equations
\omegai = \frac{3100 rpm * (2 * pi)}{60} = 324.6 rad/sec
\omegaf = \frac{1300 rpm * (2 * pi)}{60} = 136.1 rad/sec
\omegaf = \omegai + \alphat
\omegaf^{2} = \omegai^{2} + 2\alpha(\Delta\Theta)
The Attempt at a Solution
136.1 = 324.6 + 2.1 \alpha
\alpha = 89.8 rad/sec^{2}
136.1^{2} = 324.4^{2} + 2 * 89 (\Delta\Theta)
(\Delta\Theta) = 482.8 rad / (2 * pi) = 76.8 rev
Want to make sure if this is correct.