Angular Aceleration of Cilynder

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The discussion focuses on calculating the angular acceleration of a solid cylinder pivoting on a frictionless bearing when a force equal to the weight of a 0.690 kg mass is applied. The calculated angular acceleration is 6.81 rad/s². Additionally, the thread poses a second problem where a mass is hung from the string, prompting further calculations for angular acceleration and the distance the mass travels downward between specific time intervals. Participants are seeking assistance with these physics problems. The conversation emphasizes the application of rotational dynamics principles to solve the scenarios presented.
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M, a solid cylinder (M=1.79 kg, R=0.111 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.690 kg mass, i.e., F = 6.769 N. Calculate the angular acceleration of the cylinder.

Answer is: 6.81 E 1 rad/s^2

then:

If instead of the force F an actual mass m = 0.690 kg is hung from the string, find the angular acceleration of the cylinder.

How far does m travel downward between 0.450 s and 0.650 s after the motion begins?
 
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anyone can help me with that two problems above?...
 
ty... i have done this exercise... ty
 
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