Angular magnification, given F and di

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SUMMARY

The discussion focuses on calculating the angular magnification of a magnifying glass used by a jeweler with a near point of 40.0 cm and a lens focal length of 5.00 cm. The formula applied is M = (1/f - 1/q)N.P., where the virtual image distance (di) is 165 cm. The calculated angular magnification is 7.76 cm, but the correct value is 8.24 cm. The discrepancy highlights the importance of accurate calculations in optics.

PREREQUISITES
  • Understanding of lens formulas, specifically 1/f = 1/do + 1/di
  • Familiarity with the concept of angular magnification
  • Knowledge of virtual image formation in optics
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of the lens formula 1/f = 1/do + 1/di
  • Learn about different types of magnifying glasses and their applications
  • Explore the concept of virtual images in more depth
  • Investigate common errors in optical calculations and how to avoid them
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Students in physics, optical engineers, jewelers, and anyone interested in the practical applications of optics and magnification techniques.

Wamjam
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A Jeweler, whose near point is 40.0cm from his eye, is using a magnifying glass to examine a gold ring. The lens of the magnifying glass has a focal length of 5.00cm ( part C) Determine the angular magnification of the magnifying glass when the virtual image of the ring is located 165 cm from the lens.
1/f = 1/do + 1/di
M = (1/f - 1/q)N.P.
[(1/5) - (1/165)]40cm = 7.76cm (right answer is 8.24 centimeters ***edit NOT meters. just cm I am just tired and almost done my last exam*** ) and i can't figure out how to get it
 
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nvm, i didnt figure it out.
 
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