Angular Momentum:Calculating Omega with Energy Preservation Law

vlio20
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Hi to all,

the question is:

http://ufu.co.il/files/dyzh41xkp5amsfjpv4dk.png

the two sticks clash and stick one to the other, the plane is smooth friction.
the momentum of one stick (in it's own center of mass is 0.5*L^2*m).

the length of the sticks is L and the mass is m, the vertical's stick speed is v.

I have to find the angular speed (w- omega) that both sticks will rotate in, I have manged to do this with the angular momentum preservation law, and I would like to know how to this with energy preservation law.tnx

Homework Statement


Homework Equations


The Attempt at a Solution

 
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ok... my bad!
the energy is not the same before and after the clash- it is not an elastic clash
 
welcome to pf!

hi vlio20! welcome to pf! :smile:
vlio20 said:
… I would like to know how to this with energy preservation law.

you can't :redface:, it isn't! :biggrin:

(mechanical) energy is never conserved unless the question says so

in this case, it obviously isn't conserved, because the two bodies stick together, so it's a perfectly https://www.physicsforums.com/library.php?do=view_item&itemid=38"

https://www.physicsforums.com/library.php?do=view_item&itemid=53" and energy are enough to solve a problem … any extra equation (like a geometrical constraint) means that something has to go, and that's always the energy equation :wink:
 
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oops!

oops! :biggrin:
 
yes I have understand my mistake after I posted it.
the collision is a plastic and not elastic

tnx
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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