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Angular momentum quick problem please

  1. Apr 21, 2009 #1
    i seem to have got it wrong,


    http://img10.imageshack.us/img10/2373/masteringphysics.jpg [Broken]

    my solving:

    L=IW
    I=mr^2

    L=mr^2w

    L=2.7kg* (0.03^2) * w

    w= 2*pi * 600rpm /60 =62.83 rad/s

    L=2.7*0.0009*62.83 =0.15

    and i got it wrong? i was pretty sure it was right,

    help please
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Apr 21, 2009 #2

    dx

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    Gold Member

    Hi vorcil,

    The moment of inertia of the disk is ½Mr².
     
  4. Apr 21, 2009 #3

    Cyosis

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    What's the moment of inertia of a thin disk/cylinder about what is in your case the x-axis?
     
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