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Angular momentum quick problem please

  • Thread starter vorcil
  • Start date
  • #1
393
0
i seem to have got it wrong,


http://img10.imageshack.us/img10/2373/masteringphysics.jpg [Broken]

my solving:

L=IW
I=mr^2

L=mr^2w

L=2.7kg* (0.03^2) * w

w= 2*pi * 600rpm /60 =62.83 rad/s

L=2.7*0.0009*62.83 =0.15

and i got it wrong? i was pretty sure it was right,

help please
 
Last edited by a moderator:

Answers and Replies

  • #2
dx
Homework Helper
Gold Member
2,011
18
Hi vorcil,

The moment of inertia of the disk is ½Mr².
 
  • #3
Cyosis
Homework Helper
1,495
0
What's the moment of inertia of a thin disk/cylinder about what is in your case the x-axis?
 

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