Angular momentum; turntable problem

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To solve the turntable problem, the angular momentum before and after the blocks land must be conserved. The moment of inertia of the turntable is calculated using I = 0.5MR^2, and the additional masses should also be included as point masses at a distance from the center. The total moment of inertia after the blocks land is the sum of the turntable's inertia and the inertia of the two blocks. The final angular velocity can then be determined by applying the conservation of angular momentum principle. This approach effectively combines the moment of inertia of all components to find the new angular velocity.
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Homework Statement


A 1.7 kg , 20cm--diameter turntable rotates at 140rpm on frictionless bearings. Two 480g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick.

What is the turntable's angular velocity, in rpm , just after this event?


Homework Equations


L = Iω
Where L is angular momentum.
L_before = L_after

The Attempt at a Solution


I'm not sure how to calculate the moment of inertia after the masses have landed on the turntable. for the turntable i used the equation I= .5MR^2 . Do I use the same equation for the two additional masses as well and add them to the moment of inertia of the turntable? or simply add the mass to the equation. (.5*(M_table + M_1 + M_2)*R^2)*ω or (I_table + I_m1 + I_m2)ω?
 
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Treat them like point masses located at distance D/2 from the center of rotation.
 
Thank you sir, that did it
 
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