Angular Speed of Bullet: How to Calculate Rotational and Angular Speed?

AI Thread Summary
To calculate the rotational and angular speed of a bullet with a diameter of 0.5 inches and a speed of 400 feet per second, the formulas R=2πn and w=v/r are applied. The bullet makes 12.5 revolutions as it travels through a 1.5-meter gun, with each revolution covering 120 mm. The time the bullet spends in the gun is needed to determine revolutions per second and convert that to radians per second for angular speed. The diameter is relevant for calculating angular velocity, confirming its use in the formula. Understanding these calculations is essential for accurate measurements of the bullet's motion.
hitman38
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Hey guys,
I confused about something,please help me.

I have a bullet and its diameter is 0.5 inches. its speed is 400 foot /sec.
It makes one complete rotation in the gun 120 mm per turn and length of the gun is 1.5 meter.
How can I calculate the rotational and angular speed?

-I used a formula for rotational speed;
R=2pi.n n=(number of the rotation) which is 1.5 meter/1.2 mm.


- Angular speed;
w=v/r w=400 ftsec/0.5inch

Are my formulas and calculations correct?
 
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wow 1.5 meter is quite a long gun haha. anyway if i am correct 120mm is the distance the bullet travel in one round correct? i would find out how many turns it need to make before it exits the barrel and use the speed that it is traveling. As for the diameter i have no idea what it is for
 


Yes u correct 120 mm is the distance the bullet travel in one correct.
I guess the amount of the turn is 1500/120=12.5
Given diameter may be for the angular velocity; w=v/r
But I am not sure about if i can use this diameter for angular velocity.
 
You are correct. The bullet does 12.5 revolutions inside the gun.

How many revolutions per second is that? Hint: you need to find how many seconds the bullet spends in the gun.
How many radians per second is that? That is your ω, the angular speed.
 

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