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Angular Velocity on a circular platform

  1. Oct 23, 2008 #1
    A large horizontal circular platform (M=120.1 kg, r=3.45 m) rotates about a frictionless vertical axle. A student (m=73.3 kg) walks slowly from the rim of the platform toward the center. The angular velocity w of the system is 3.9 rad/s when the student is at the rim. Find w (in rad/s) when the student is 2.47 m from the center.

    Does the angular velocity w is not the same everywhere in the circular platform?...
    i put 3.9 rad/s and the answer was wrong
  2. jcsd
  3. Oct 23, 2008 #2
    i use de I1W1=I2W2

    if I= (1/2)Mr^2 then:


    finding out for... W2= [(R1^2) / (R2^2)]* W1

    W2= [(3.45^2)/(2.47^2)]*(3.9)
    W2= 7.61 rad/s

    the answer is wrongs....Can anyone help me plz...
  4. Oct 25, 2008 #3


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    Homework Helper

    Hi Naldo6,

    This equation is not correct. The angular momentum is not conserved for the student alone or the platform alone; it is conserved for the combination (platform+student). This means that the rotational inertia I has to be that of the combination (platform+ student).

    So for your equation I1W1=I2W2 :

    I1 = (initial I for platform) + (initial I for student)

    and a similar quantity for I2. Do you get the right answer?
  5. Oct 26, 2008 #4
    ty it gives me the correct answer with ur suggestion...
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