Annihilation/creation operator question

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But in quantum field theory, the observables are found by integrating the Hamiltonian over spacetime, not by applying operators.In summary, these operators increase/decrease occupation number by one particle. They do not represent physical processes or observables, but are useful in quantum field theory. Only self-adjoint operators are considered observables in QM, but in QFT, observables are found by integrating the Hamiltonian over spacetime, not by applying operators.
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KevinMcHugh
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These operators increase/decrease occupation number by one particle. What observable do these operators represent?
I'm just curious what physical processes these operators represent. Since particles are created/destroyed in pairs, do they have to applied twice to describe an actual process?
 
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KevinMcHugh said:
Summary: These operators increase/decrease occupation number by one particle. What observable do these operators represent?

I'm just curious what physical processes these operators represent. Since particles are created/destroyed in pairs, do they have to applied twice to describe an actual process?
They don't represent physical processes or observables (they're not self adjoint or unitary). They're just formal operators useful in quantum field theory.

Wigner managed to find a way to classify all particle states in Minkowski spacetime. With each type there is an associated creation/annihilation operator and free quantum fields ultimately turn out to be just (generalized) Fourier transforms of them.
 
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Thank you DarMM. I was under the assumption operators represent observables in QM.
 
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KevinMcHugh said:
Thank you DarMM. I was under the assumption operators represent observables in QM.
Only self-adjoint operators do. And even then there are questions over whether all do.
 
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1. What is the difference between annihilation and creation operators?

The annihilation operator, denoted by a, is used to remove a particle from a quantum system. The creation operator, denoted by a, is used to add a particle to a quantum system. They are essentially inverse operations.

2. How are annihilation and creation operators related to each other?

The annihilation and creation operators are related by the commutation relation [a, a] = 1, which means that they do not commute and their order matters. This relation is a fundamental property of quantum systems.

3. What is the significance of the commutation relation for annihilation and creation operators?

The commutation relation for annihilation and creation operators is important because it allows us to define the number operator, N = aa, which counts the number of particles in a quantum system. This operator is used to describe many important physical phenomena, such as quantum states and energy levels.

4. How are annihilation and creation operators used in quantum field theory?

In quantum field theory, annihilation and creation operators are used to describe the creation and annihilation of particles in a quantum field. They are used to construct field operators, which are used to describe the dynamics of particles and interactions between them.

5. Can annihilation and creation operators be used to describe any type of particle?

Yes, annihilation and creation operators can be used to describe any type of particle, including bosons and fermions. However, the specific form of the operators may differ depending on the type of particle being described. For example, the operators for fermions must satisfy different commutation relations than those for bosons.

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