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Another inverse trig function

  1. Jan 28, 2010 #1
    Let f(x) = sqrt(49-x^2) + 7arccos(x/7).

    Then f'(x) can be written in the simplified form -((x+c)/(mx+n))^p

    What are the values of c, m, n and p?

    So far what I got in simplified form is (-x-7)/sqrt(49-x^2)

    How can I make my simplified form into that simplified form?
  2. jcsd
  3. Jan 28, 2010 #2


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    Hi shiri! :smile:

    (try using the X2 tag just above the Reply box :wink:)

    Hint: 49 - x2 = (7 + x)(7 - x) :smile:
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