Another motion in 2 dimensions ?

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The ball is thrown at a speed of 25.0 m/s and an angle of 40 degrees, reaching a wall 22.0 m away. It hits the wall 18.8 m above the release point. The horizontal component of its velocity upon impact is 19.7 m/s, while the vertical component is 16.4 m/s. The ball has already passed the highest point of its trajectory when it strikes the wall. This analysis confirms the motion dynamics in two dimensions.
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You throw a ball toward a wall at speed 25.0 m/s and at angle 40 degrees above the horizontal . The wall is distance d=22.0 m from the release point of the ball. (a) How far above the release point does the ball hit the wall? What are the (b) horizontal and (c) vertical components of its velocity as it hits the wall? (d) When it hits, has it passed the highest point on its trajectory?





as for A could you
could you treat it as s right triangle and since d = 22 m that could be the adjacent side. Then using that and the angle solve for the other two sides giving you the height?
 
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a) The ball hits the wall 18.8 m above the release point. b) The horizontal component of its velocity as it hits the wall is 19.7 m/s. c) The vertical component of its velocity as it hits the wall is 16.4 m/s. d) Yes, it has passed the highest point on its trajectory.
 
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