Another Photoelectric effect problem

creativepinky
Messages
3
Reaction score
0

Homework Statement



In a photoelectric-effect experiment, light of wavelength (x) nm is incident on a sample of sodium. The work function of sodium is (y) J. Calculate the stopping potential required to just stop all electrons from reaching the anode.

Homework Equations



To work out frequency, I've used taken c= λ ×f, therefore f= c/λ
which can now be put into:

1/2 m_e v_max^2=hf- ϕ

(which can then be used in the equation v_max=eV_stop to work out the stopping potential.)

The Attempt at a Solution



My question is do you take the value for the electron rest mass (m_e) as 9.109 x 10^-31 to calculate this or do you need to multiply this by the number of electrons that are within sodium (11) and then use this for the value of m_e?

Many thanks in anticipation.
 
Physics news on Phys.org
creativepinky said:

Homework Statement



In a photoelectric-effect experiment, light of wavelength (x) nm is incident on a sample of sodium. The work function of sodium is (y) J. Calculate the stopping potential required to just stop all electrons from reaching the anode.

Homework Equations



To work out frequency, I've used taken c= λ ×f, therefore f= c/λ
which can now be put into:

1/2 m_e v_max^2=hf- ϕ

(which can then be used in the equation v_max=eV_stop to work out the stopping potential.)

The Attempt at a Solution



My question is do you take the value for the electron rest mass (m_e) as 9.109 x 10^-31 to calculate this or do you need to multiply this by the number of electrons that are within sodium (11) and then use this for the value of m_e?

Many thanks in anticipation.

You mean KE_{max} = eV_{stop} right? If you multiplied by 11 wouldn't that mean the individual photon released 11 electrons from the atom? Do you even need to use m_e?
 
K.E max =eVstop = h(f-f0)=hc/λ - y (Work function)

where f is freq, f0 is cutoff freq

the work function (y) can be related
f0 = y/h = c/λ0


hope that helps
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top