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Another problem

  1. Feb 19, 2007 #1
    A sports car, picking up speed, passes between two markers in a time of 4.1s. The markers are separated by 120m. All the while, the car accelerates at 1.8m/s^2. What is its speed at the second marker?

    Here is what i did:

    d = vi(t)+1/2(a)t^2
    120=vi(4.1)+1/2(1.8)(4.1)^2
    29.3=vi+15.1
    vi=14.2m/s

    d=1/2(vi+vf)t
    120=1/2(14.2+vf)(4.1)
    vf=44.3m/s
    vf=25.2m/s
     
  2. jcsd
  3. Feb 19, 2007 #2

    radou

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    Homework Helper

    Your calculation is wrong. Check the numbers once again.
     
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