Another roller coaster question

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Homework Help Overview

The discussion revolves around a physics problem related to forces acting on a roller coaster at different points in its loop, specifically analyzing normal force and gravitational force. The context includes calculations involving weight at the bottom and top of the loop.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between normal force and gravitational force at different points on the roller coaster. Questions are raised about determining acceleration and time for one loop, as well as the minimum and maximum weights experienced by the coaster.

Discussion Status

There are various approaches being explored, with some participants suggesting different methods to derive equations based on the forces involved. While some calculations have been attempted, there is no explicit consensus on the correct values or methods, and uncertainty remains regarding the results obtained.

Contextual Notes

Participants express confusion over the calculations and the need for clarity on how to derive certain values, such as velocity and mass, from the given forces. There is an indication of differing answers for the mass of the coaster at different points, which adds to the complexity of the discussion.

vorcil
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http://img13.imageshack.us/img13/9297/masteringphysicsq1.jpg

At the bottom it's 510N, Top 666N,

at bottom Fnormal=netforce= mv^2/r + mg

http://img13.imageshack.us/img13/8244/masteringphysicsq1g.jpg
-my attempt

I'm not sure how to figure out the acceleration
or determine the time for one loop on the graph.
 
Last edited by a moderator:
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great 510 n = 5 seconds...
666n = 15 seconds
 
I don't think you need to determine the period or the velocity.

Where will the weight be the minimum? And the maximum?

Presuming that the ferris wheel is not a super spinning Whirl-a-Gig, then you know

mg - mv2/r = Min
mg + mv2/r = Max

Then just solve for m*g.
 
LowlyPion said:
I don't think you need to determine the period or the velocity.

Where will the weight be the minimum? And the maximum?

Presuming that the ferris wheel is not a super spinning Whirl-a-Gig, then you know

mg - mv2/r = Min
mg + mv2/r = Max

Then just solve for m*g.

I got two different awnsers, for the coaster at the bottom 12.171kg and top 14.52kg
i think I've done it wrong :\
 
vorcil said:
I got two different awnsers, for the coaster at the bottom 12.171kg and top 14.52kg
i think I've done it wrong :\

Try constructing the equations.

Then subtract 1 from the other.

You will determine then what mv2/r is and then you can figure the weight from either of the 2 equations.

I only get 1 answer.
 
LowlyPion said:
Try constructing the equations.

Then subtract 1 from the other.

You will determine then what mv2/r is and then you can figure the weight from either of the 2 equations.

I only get 1 answer.

What like?
666-510 = (mg + mv^2/r) - (mg - mv^2/r)
i can't figure out the velocity for the mv^2/r
 
666 = mg + mv^2/r
510 = mg - mv^2/r

666+510 = 2mg + - mv^2/4
= 1176 = 2mg
1176/9.8 = 120
120/2 = 60

60kg?
 
vorcil said:
666 = mg + mv^2/r
510 = mg - mv^2/r

666+510 = 2mg + - mv^2/4
= 1176 = 2mg
1176/9.8 = 120
120/2 = 60

60kg?

That's right. Adding them works too. In fact better as it yields the m*g directly.

m = 1176/(2*9.8) = 60
 

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