Another SUVAT and Newton's Second Law Question

AI Thread Summary
The problem involves calculating the additional retarding force due to brakes on a car with a mass of 1500kg, initially traveling at 48 km/h, which comes to a stop over 50m. Using the SUVAT equation, the deceleration was calculated as 1.77 m/s², leading to a net retarding force of 2655N. To find the force exerted by the brakes, the constant resisting force of 980N must be subtracted from the net force. This results in a brake force of 1675N. The calculations confirm the application of Newton's Second Law and SUVAT principles effectively.
Apothem
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Homework Statement



"The constant force resisting the motion of a car of mass 1500kg is 980N. If, when traveling at 48kmhr-1, the car is brought to rest in a distance 50m by applying the brakes, find the additional retarding force due to the brakes (assumed constant)

Homework Equations



SUVAT: v2=u2+2as, rearranged to a=(v2-u2)/2s

Newton's Second Law: F=ma

The Attempt at a Solution



I used suvat (s=50m , u=48kmhr-1=13.3ms-1 [3.S.F.] , v=0ms-1 , a=a , t=t) to calculate the deceleration as 1.77ms-2 [3.S.F.], I then used F=ma, and found the force to be 2655N, is this right?
 
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Apothem said:

Homework Statement



"The constant force resisting the motion of a car of mass 1500kg is 980N. If, when traveling at 48kmhr-1, the car is brought to rest in a distance 50m by applying the brakes, find the additional retarding force due to the brakes (assumed constant)

Homework Equations



SUVAT: v2=u2+2as, rearranged to a=(v2-u2)/2s

Newton's Second Law: F=ma

The Attempt at a Solution



I used suvat (s=50m , u=48kmhr-1=13.3ms-1 [3.S.F.] , v=0ms-1 , a=a , t=t) to calculate the deceleration as 1.77ms-2 [3.S.F.], I then used F=ma, and found the force to be 2655N, is this right?

2655N is the net retarding force.

There are two retarding forces acting on the car.You need to deduct the constant force of 980N from the net force to get the force due to brakes .
 
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