Another thermal expansion problem

AI Thread Summary
The discussion centers on a thermal expansion problem involving a vertical glass tube filled with liquid, where the height change of the liquid column is calculated as the temperature increases from 20°C to 30°C. Participants debate the relevance of the tube's length and radius, concluding that these dimensions do not affect the height change of the liquid, as they cancel out in calculations. The focus shifts to the independent calculations of volume expansion for both the liquid and the tube, emphasizing the need to consider their respective coefficients of expansion. One participant estimates a height change of 0.14 mm for the liquid column. The conversation highlights the importance of understanding thermal expansion principles in solving such problems.
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Homework Statement



A vertical glass tube of length L = 1.2800000 is half-filled with a liquid at 20.0000* C. How much will the height of the liquid column change when the tube is heated to 30.0000*C?

Glass linear expansion co = 1e-5/K
Liquid volume expansion co = 4e-5/K

Homework Equations





The Attempt at a Solution



I don't understand why the length of the tube matters other than as giving me the initial height of the liquid. Shouldn't I be given the radius of the tube instead? How far the length of the tube grows has absolutely no effect on how much the height of the liquid changes, but the space within the tube does..
 
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The circumference of the tube will change. Hope this helps
 
The length of the tube doesn't matter nor does its radius (cancels out). It looks like you will need to calculate the Δ length the tube and liquid by ΔV/ΔA for each independently. Remember that γ=2α and β=3α. I am guessing that ΔV/ΔA for liquid will be greater than ΔV/ΔA for the tube.
 
I got ΔL = 0.14mm. Do you have an answer?
 
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