Find the Solve the Problem with Force!

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In summary, the problem involves a 200N box being slid slowly through a 20m track with a friction coefficient of 0.2. The task is to find the work done by the force acting on the box at an angle 'A' with the horizontal. Some potential solutions have been suggested, but it seems that the angle 'A' is necessary for a definitive answer. The coefficient of friction may also affect the outcome.
  • #1
cool2think
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Answer Problem!

A BOX WEIGHIN 200N IS 2 B SLID SLOWLTHROUGH 20 M ON A ROUGH STRAIGHT TRACKFRICTION COEFF=O.2I HAV 2 FIND THE WORK DONE BY THE FORCE ACTIN ON THE BOX!IF THE FORCE ACTS AT AN ANGLE 'A'WITH THE HORIZONTAL!
I CANT GET THE ANSWER!
 
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  • #2
Please tell us your thoughts on the problem, and what you have come up with so far.

- Warren
 
  • #3
W = Fd

The force must be parallel with the displacement! F is not the total force applied to the box. F is actually the force applied * cos([tex]\theta[/tex]).
 
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  • #4
ok... unless u know the angle A i doubt this problem can be solved... most prolly the coef. of friction is coef. of kinetic friction... so then the force of friction is (coef.)*mass*g and so the work done by it is distance*force of friction (jsut as shawn said). But if the coef. of friction is static friction, then this problem can't be solved. coz the work done by friction cud be 0 if the applied force is insufficient to move the block
 

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