1. Mar 8, 2004

### cool2think

A BOX WEIGHIN 200N IS 2 B SLID SLOWLTHROUGH 20 M ON A ROUGH STRAIGHT TRACKFRICTION COEFF=O.2I HAV 2 FIND THE WORK DONE BY THE FORCE ACTIN ON THE BOX!IF THE FORCE ACTS AT AN ANGLE 'A'WITH THE HORIZONTAL!!

2. Mar 8, 2004

### chroot

Staff Emeritus
Please tell us your thoughts on the problem, and what you have come up with so far.

- Warren

3. Mar 8, 2004

### ShawnD

W = Fd

The force must be parallel with the displacement! F is not the total force applied to the box. F is actually the force applied * cos($$\theta$$).

Last edited: Mar 8, 2004
4. Mar 11, 2004

### karanrustagi

ok... unless u know the angle A i doubt this problem can be solved.... most prolly the coef. of friction is coef. of kinetic friction.... so then the force of friction is (coef.)*mass*g and so the work done by it is distance*force of friction (jsut as shawn said). But if the coef. of friction is static friction, then this problem can't be solved. coz the work done by friction cud be 0 if the applied force is insufficient to move the block