Antiderivative of 4-3(1+x^2)^-1 | Graph Comparison

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Homework Statement


Find the antiderivative F of f that satisifies the given condition. Check by comparing the graphs of f and F.

f(x)=4-3(1+x^2)^-1
F(1)=0


Homework Equations





The Attempt at a Solution


So far what I attempted to do was this:

F(x)=4x -3tan^-1(x) + C
but was unsure from here on.
 
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Just plug in the given value for F(1) = 0 and solve for C.
 
Ok so my F(x) is correct?

That was probably the part I needed the most assurance with.
 
master1425 said:

Homework Statement


Find the antiderivative F of f that satisifies the given condition. Check by comparing the graphs of f and F.

f(x)=4-3(1+x^2)^-1
F(1)=0


Homework Equations





The Attempt at a Solution


So far what I attempted to do was this:

F(x)=4x -3tan^-1(x) + C
but was unsure from here on.
(4x)'= 4 and
(-3 arctan(x))'= -3/(x2+1)
so what is F' ?

F(1)= 4(1)- 3arctan(1)+ C= 0. C= ?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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