Any conclusions about the gaps between p and p^2?

  • Thread starter Thread starter maris205
  • Start date Start date
maris205
Messages
3
Reaction score
0
In sieve method, we could get the prime numbers between p and p^2 applying the primes less than prime number p.

Is there any conclusion about the gap of these primes? Some conjectures show the upper bound of primes gaps before p is g(p)< ln(p)^2 or g(p)<p^(1/2) (If RH is true).

But here we just consider the primes between p and p^2, which are filtered by determinate primes. So I want to know whether we could get some easy conclusions about their gaps by elementary number theory. For example, could we prove the gap of the primes between p and p^2 is less than p? My calculation shows it’s true.
 
Last edited:
Physics news on Phys.org
maris205 said:
Is there any conclusion about the gap of these primes? Some conjectures show the upper bound of primes gaps before p is g(p)< ln(p)^2 or g(p)<p^(1/2) (If RH is true).

RH would imply g(p)=O((log p)*p^(1/2)), not p^(1/2).

I don't know whose conjecture your g(p)< ln(p)^2 is referring to? There's Cramer's that says the lim sup of g(p)/log(p)^2 is 1 but this doesn't imply your inequality.

But here we just consider the primes between p and p^2, which are filtered by determinate primes. So I want to know whether we could get some easy conclusions about their gaps by elementary number theory. For example, could we prove the gap of the primes between p and p^2 is less than p? My calculation shows it’s true.

What's a "determinate prime"? Knowing the largest gap between p and p^2 is p implies the largest gap less than p is p^(1/2) (just consider a prime larger than sqrt(p) and apply this again, and repeat). Since this is quite a large leap from current results (and stronger than what RH implies) you're going to have to provide something stronger than "My calculation show's it's true" before I come near believing you can prove this.
 
p=13, p^2=169, 113 and 127 are prime, no number between them is prime (5|115, 9|117, 7|119, 11|121, 3|123, 5|125), and 127-113=14>13.

Thankfully there is a small example to find by inspecting a table of primes. I doubt that this is is an isolated example.
 
It would seem suprising if that wasn't isolated (barring including consecutive primes like 7,11 where only one lies between 3 and 3^2). See

http://primes.utm.edu/notes/GapsTable.html

The numerical evidence points to gaps quite a bit smaller than we can prove at this point.
 
That link brings up one question: which definition of difference is the OP using: p-q or p-q-1? The latter makes my counter example false, but I assumed the former, naively.

The gaps are indeed far smaller than I anticipated.
 
p-q or p-q-1, either way a finite number of counter examples (or none) seems likely.

If p(g) is the prime following the first occurance of a gap of length at least g, it's conjectured that log p(g)~sqrt(g). The maximum gap length seems to grow very slowly. Given the average gap between primes less than x is log(x), it's maybe not too suprising.

The basic proof that there are arbitrarily large gaps doesn't usually stress just how big the number constructed is. A gap of length n-1 following n!+1 is pretty short considering just how large n! is (of course the actual gap here may be bigger, you'd take the largest prime less than n!+2, etc).
 
##\textbf{Exercise 10}:## I came across the following solution online: Questions: 1. When the author states in "that ring (not sure if he is referring to ##R## or ##R/\mathfrak{p}##, but I am guessing the later) ##x_n x_{n+1}=0## for all odd $n$ and ##x_{n+1}## is invertible, so that ##x_n=0##" 2. How does ##x_nx_{n+1}=0## implies that ##x_{n+1}## is invertible and ##x_n=0##. I mean if the quotient ring ##R/\mathfrak{p}## is an integral domain, and ##x_{n+1}## is invertible then...
The following are taken from the two sources, 1) from this online page and the book An Introduction to Module Theory by: Ibrahim Assem, Flavio U. Coelho. In the Abelian Categories chapter in the module theory text on page 157, right after presenting IV.2.21 Definition, the authors states "Image and coimage may or may not exist, but if they do, then they are unique up to isomorphism (because so are kernels and cokernels). Also in the reference url page above, the authors present two...
When decomposing a representation ##\rho## of a finite group ##G## into irreducible representations, we can find the number of times the representation contains a particular irrep ##\rho_0## through the character inner product $$ \langle \chi, \chi_0\rangle = \frac{1}{|G|} \sum_{g\in G} \chi(g) \chi_0(g)^*$$ where ##\chi## and ##\chi_0## are the characters of ##\rho## and ##\rho_0##, respectively. Since all group elements in the same conjugacy class have the same characters, this may be...
Back
Top