Any hints on how to do I find the x component?

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To find the x component of the force, it's essential to recognize that the force is not constant and increases from zero at x=0, necessitating the use of integration. The initial calculation of work using a constant force of 33.5N over 16m resulted in an incorrect value of 537 J. When attempting to integrate the force, the formula used was (2(ax^(5/2))/5, leading to a result of 214.6 J, which was also incorrect. Participants suggest double-checking the arithmetic in the integration process to identify any errors. Accurate calculations are crucial for determining the correct work done.
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Homework Statement



force.png


Homework Equations



Work = F xcomponent * delta x

The Attempt at a Solution


The force is given as a resultant since it does not give a specificed x or y component. Any hints on how to do I find the x component?
 
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It states that the force points in the x direction.
 
Doc Al said:
It states that the force points in the x direction.

if that's the case the force would 33.5N , the work will be (33.5N)(16m) = 537 J which was wrong. I do not get where did I go wrong if all the information is given.
 
warnexus said:
if that's the case the force would 33.5N , the work will be (33.5N)(16m) = 537 J which was wrong. I do not get where did I go wrong if all the information is given.
The force is not constant in magnitude. It increases from 0 (at x=0). You'll need to use integration.
 
haruspex said:
The force is not constant in magnitude. It increases from 0 (at x=0). You'll need to use integration.

if I have to use integration on force then it will be (2(ax^(5/2))/5 .

plugging in the value of a and x= 16m I got 214.6 J <- which is wrong. where did I go wrong?
 
warnexus said:
if I have to use integration on force then it will be (2(ax^(5/2))/5 .
That looks OK.
plugging in the value of a and x= 16m I got 214.6 J <- which is wrong.
Double check that arithmetic.
 
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