AP Physics: Momentum Change Calculated for Dropped Ball

Thread starter Silverbolt
Start date Oct 23, 2012
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Ap Ap physics Ball Ground Momentum Physics

AI Thread Summary

The discussion focuses on calculating the change in momentum for a 3.0-kg ball dropped from a height, which strikes the ground at 16.0 m/s and rebounds at -12.0 m/s. The formula for momentum, p = mv, is applied to determine the change in momentum by subtracting the initial momentum from the final momentum. Participants emphasize that momentum is a vector quantity, highlighting the importance of direction and sign in calculations. The conversation reinforces the need to consider both magnitude and direction when analyzing momentum changes. Understanding these principles is crucial for solving similar physics problems effectively.

Oct 23, 2012

Silverbolt

A 3.0-kg ball, which is dropped, strikes the ground with a velocity of 16.0 m/s and rebounds with a velocity of -12.0 m/s. What is the change in momentum?

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Oct 23, 2012

Same-same

Remember the formula for momentum?

Oct 23, 2012

Silverbolt

p=mv ?

Oct 23, 2012

Same-same

Yes. Now how does that apply to the problem? If p = mv, what is change in p?

Oct 23, 2012

Silverbolt

mv final-mv inital

Oct 23, 2012

Same-same

Yep. Now is momentum a vector quantity? Does the sign matter?

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