Apparent vs. actual speed for moving star

  • Thread starter Thread starter QuantumCurt
  • Start date Start date
  • Tags Tags
    Speed Star
Click For Summary
SUMMARY

The discussion focuses on the concept of apparent speed versus actual speed in the context of astronomical observations. The problem illustrates how a star moving at speed v at an angle θ can appear to travel faster than the speed of light due to the time it takes for light to reach Earth. The apparent speed is calculated using the formula vapparent = v sin θ, where the maximum apparent speed occurs at θ = 90 degrees. The conversation highlights the importance of understanding light travel time in interpreting astronomical data.

PREREQUISITES
  • Understanding of basic trigonometry and angles
  • Familiarity with the concept of light travel time
  • Knowledge of special relativity principles
  • Ability to interpret astronomical observations
NEXT STEPS
  • Research the implications of light travel time in astrophysics
  • Study the mathematical foundations of special relativity
  • Explore the concept of parallax in astronomy
  • Learn about the limitations of observational astronomy
USEFUL FOR

Astronomy students, physics educators, and anyone interested in the nuances of astronomical observations and the principles of special relativity.

QuantumCurt
Education Advisor
Messages
726
Reaction score
166
This is for a classed called Special Relativity and Math Methods. This problem doesn't involve special relativity though, since it's all from the same frame of reference.

1. Homework Statement

Every 2 years, more or less, The New York Times publishes an article in which some astronomer claims to have found an object traveling faster than the speed of light. Many of these reports result from a failure to distinguish what is seen from what actually happens– that is, from a failure to account for light travel time. Here’s an example: A star is traveling with speed v at an angle θ to the line of sight from Earth. Astronomers on Earth observe the star thanks to the light it emits, which travels from the moving star to their telescopes. The figure below shows the situation, with the thick arrow denoting the path of the star, and the vertical thin arrows denoting the light rays seen by the astronomers.

(a) What is the star’s apparent speed across the sky? Let me clarify a bit: Let a and b be two positions along the star’s path. Suppose the light signal from point a reaches the Earth at time Ta while the signal from point b arrives at time Tb. LetΔT≡Tb–Ta be the difference between these arrival times. Further, let Δs be the distance the star traveled across the celestial sphere between points a and b, i.e., the distance it moved in the only direction the astronomers can perceive: perpendicular to their line of sight. The apparent speed of the star is Δs/ΔT→that’s what you need to calculate.​

(b) What angle θ gives the maximum apparent speed?

(c) Show explicitly that the apparent speed can be much greater than c, even if v itself is less than c. Hint: a quick way to accomplish this is by finding specific values of v and θ that give the result you seek.

Here's the included diagram:
phy225.PNG


The Attempt at a Solution



In my attempt I considered the path of the star to simply be ##v\Delta{T}##, giving it the same units as ##\Delta{S}##. The apparent speed of the star is ##\frac{\Delta{S}}{\Delta{T}}##

$$sin \theta=\frac{\Delta{S}}{v \Delta{T}}$$

So

$$\frac{\Delta{S}}{\Delta{T}}=v_{apparent}=v sin \theta$$

This seems valid to me, but it doesn't make sense in the context of the rest of the problem. Obviously for part b the maximum speed would be when ##sin \theta=1##, which is at 90 degrees. But part c states that this relationship can show an apparent speed much greater than c, which this equation does not show, given that v is less than c.

Any input would be very appreciated!
 
Physics news on Phys.org
The problem statement's missing a parallax distance/measurement somewhere. @marcus
 
I didn't really get the impression that it was missing any information. I think they're just looking for a symbolic solution here.
 
o:) Nothing missing.
QuantumCurt said:
v apparent =vsinθ
sinθ = 0 to 1; vapp/(0 to 1) = "v. "
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
Replies
8
Views
835
  • · Replies 10 ·
Replies
10
Views
3K
Replies
23
Views
2K
Replies
8
Views
2K
Replies
4
Views
2K
Replies
3
Views
10K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K