What Is the Apparent Weight of a Person at the Bottom of a Ferris Wheel?

AI Thread Summary
The discussion focuses on calculating the apparent weight of a person at the bottom of a Ferris wheel after determining the time for one complete rotation. The person’s apparent weight at the top is 0N, and using the radius of the Ferris wheel (50m), the speed at the bottom is calculated to be 22.1 m/s, leading to a rotation time of 14.2 seconds. The user initially struggles with applying the equations for apparent weight but eventually realizes they can use the known mass from previous calculations to find the apparent weight at the bottom. The final solution confirms that understanding the relationship between true weight and apparent weight is key to solving the problem. The discussion highlights the importance of applying physics concepts to real-world scenarios.
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Homework Statement



So if a person's apparent weight at the top of a ferris wheel is 0N find the time it takes the ferris wheel to make on rotation.

Then find the apparent weight of a person at the bottom of the ferris wheel for the same person on the same ferris wheel?

Homework Equations



a=v2/r

v=2pi(r)/T

The Attempt at a Solution



So to find the time i did the following.

a=9.8 m/s2
r=50m

9.8=v2/50
v=22.1 m/s

22.1=2pi(50)/T

T=14.2 seconds

Now i am not sure what to do to find the apparent weight of the person when he or she is at the bottom of the ferris wheel. I know i have all the information i need i just am having a little trouble starting :(

I know...

N - mg = m v^2 / r

N = mg + m v^2 / r

but i am not sure how to use these to find the apparent weight...

Can someone give me a little push please :)

Thank you
 
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never mind i got it. It was for the same passenger as used in earlier parts of the problem so i already know his true weight and therefore his mass which allowed me to find his apparent weight at the bottom :)
 

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