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Apparent Weight of a Pendulum

  1. Nov 24, 2013 #1
    1. The problem statement, all variables and given/known data

    I am trying to determine the apparent weight while on a trapeze/pendulum. So far, I have heard that the apparent weight is either: a. the Fnet of all vertical forces (aka Centripetal force) and b. it is the force of tension. I am not sure which it is.

    2. Relevant equations
    a. Fnet/Fn/Fc=mv^2/r=Ft-mg cos (theta)

    b. Fnet/Fc=mv^2/r= Ft - mg cos (theta); Ft=Fc + mg
    Ft=Fn
    so: Fn= Fc + mg

    FBD is attached
    3. The attempt at a solution

    The solution is either
    Fn= Fc + mg
    or
    Fn= mv^2 /r

    However, I don't know the reasons why either of these would be correct
     

    Attached Files:

  2. jcsd
  3. Nov 24, 2013 #2

    PhanthomJay

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    The apparent weight of a person is the force that the person exerts on the 'object' in contact with the person.
     
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