Which of these two decays is more likely using the CKM matrix?

InsertName
Messages
26
Reaction score
0

Homework Statement



I'm trying to get familiar with how to use the CKM matrix when tackling such questions as "which of these two decays is more likely".

My example question is:

Which is more likely c\bar{d} ---> s\bar{d} or c\bar{d} ---> d\bar{d}


Homework Equations



The relationship between the weak eigenstates, the CKM matrix and the mass eigenstates:
(\acute{d}) (Vud Vus Vub) (d)
(\acute{s}) = (Vcd Vcs Vcb) (s)
(\acute{t}) (Vtd Vts Vtb) (t)

The Attempt at a Solution



I don't actually know where to start because I'm not sure how to use the CKM matrix in this way.

Here's my best guess:

The difference between the two interactions is that one has c--->s and the other has c--->d and the value of the element Vcd < Vcs so the most likely is c--->s so the most likely decay is c\bar{d} ---> s\bar{d}.

Any help with this is much appreciated.
 
Physics news on Phys.org
Just add absolute values to your inequality (since the entries in the CKM matrix are generally complex), and you should be fine.
 
Cool, thanks.
 
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...

Similar threads

Back
Top