Apply the Legendre Transformation to the Entropy S as a function of E

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SUMMARY

The discussion focuses on applying the Legendre Transformation to the entropy function S as a function of energy E, volume V, and particle number N. The key steps involve expressing the differential of entropy, ds, in terms of these variables and transforming it to obtain a new potential, specifically free energy F, with natural independent parameters (T, V, N). The Sackur-Tetrode equation is referenced as a goal in this transformation process, highlighting the importance of understanding differentials in thermodynamic potentials.

PREREQUISITES
  • Understanding of thermodynamic potentials, specifically entropy S and free energy F.
  • Familiarity with the Legendre Transformation in thermodynamics.
  • Knowledge of differential calculus as applied to thermodynamic equations.
  • Basic concepts of statistical mechanics, including the Sackur-Tetrode equation.
NEXT STEPS
  • Study the Legendre Transformation in detail, focusing on its applications in thermodynamics.
  • Learn how to derive the Sackur-Tetrode equation from first principles.
  • Explore the relationship between entropy and free energy in thermodynamic systems.
  • Investigate the use of differentials in thermodynamic equations and their implications.
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Students and professionals in physics, particularly those studying thermodynamics and statistical mechanics, as well as researchers interested in the mathematical foundations of thermodynamic potentials.

GravityX
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Homework Statement
Apply Legendre Transformation to Entropy
Relevant Equations
##g(m)=f(x(m))-m*x(m)## and ##x(m)=(f')^-1(m)##
Hi,

Unfortunately I am not getting anywhere with task three, I don't know exactly what to show

Bildschirmfoto 2022-11-28 um 16.30.54.png

Shall I now show that from ##S(T,V,N)## using Legendre I then get ##S(E,V,N)## and thus obtain the Sackur-Tetrode equation?
 
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You should rather think in terms of differentials. The "natural independent parameters" for ##S## are ##(E,V,N)##. Now you want to get another potential with the "natural independent parameters" ##(T,V,N)##. So first write down the differential ##\mathrm{d} S## in terms of ##(E,V,N)## and then think about, how to Legendre transform to a new potential with the other set of independent parameters.
 
Thanks vanhees71 for your help 👍

I have now represented ##ds## as follows

$$ds=\frac{\partial S}{\partial E}dE+\frac{\partial S}{\partial V}dV+\frac{\partial S}{\partial N}dN$$

$$ds=\frac{1}{T}dE+\frac{P}{T}dV-\frac{\mu }{T}dN$$

Now I would just have to get rid of the ##dE## or rather I would have to express ##dE## with the help of ##dT##, ##dV##, ##dN##, right?
 
Write it in the form of ##\mathrm{d} E=...## then find a new potential, ##F## ("free energy"), such that instead of a differnetial with ##\mathrm{d} s##, ##\mathrm{d} V## and ##\mathrm{d}N## you get one with ##\mathrm{d} T##, ##\mathrm{d}V## and ##\mathrm{d}V##. Note that
$$\mathrm{d}(Ts)=s \mathrm{d} T + T \mathrm{d} s!$$
 
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Thanks for your help vanhees71 👍 I think I got it now 😀
 

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