1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Applying ln to a graph: where would it be continuous?

  1. Dec 18, 2011 #1
    1. The problem statement, all variables and given/known data
    IMG_0557.jpg

    2. Relevant equations

    I'm looking over in old midterm to prepare for a final and can't figure out what the correct answer is. No answers were ever given. I'm not cheating on anything, would just like to know what the correct answer is and why :)

    3. The attempt at a solution
    I think the answer is either B or C but I can't decide.
     
  2. jcsd
  3. Dec 18, 2011 #2

    SammyS

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

    What is the domain of ln(u) ?
     
  4. Dec 19, 2011 #3
    um positive numbers only.
     
  5. Dec 19, 2011 #4

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    Ok, so where is g(x) positive?
     
  6. Dec 20, 2011 #5
    from zero to infinity
     
  7. Dec 20, 2011 #6

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    I meant for what values of 'x' is g(x) positive? That's what you need to know.
     
  8. Dec 20, 2011 #7

    SammyS

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

    The question is: "For what values of x is g(x) greater than zero?" Don't forget that in order for g(x) > 0, x must also be in the domain of g.
     
  9. Dec 20, 2011 #8
    ohh okay. so the answer is B?
     
  10. Dec 20, 2011 #9

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    B is right.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Applying ln to a graph: where would it be continuous?
  1. Sketching ln graph (Replies: 3)

  2. Where is f continuous? (Replies: 2)

Loading...