Archimedes' principle and the column of water

  • I
  • Thread starter abrek
  • Start date
  • Tags
    Phisics
  • #1
abrek
4
1
TL;DR Summary
If go
If you assemble the structure shown in the picture into a large container of water, lower the smaller container onto a special movable platform (red). Will the volume of displaced water be equal to the volume of the smaller container (M) according to Archimedes’ principle, or will the fact that the release of liquid occurs at a height, the water column will create resistance and less water will come out in volume?
 

Attachments

  • Без названия1_20240505173630.png
    Без названия1_20240505173630.png
    5.8 KB · Views: 6
  • Без названия1_20240505174108.png
    Без названия1_20240505174108.png
    6.5 KB · Views: 7
  • Без названия1_20240505173630.png
    Без названия1_20240505173630.png
    5.8 KB · Views: 10
  • Без названия1_20240505174108.png
    Без названия1_20240505174108.png
    6.5 KB · Views: 4
Physics news on Phys.org
  • #2
The question has nothing to do with the Archimedes principle. It has to do with the incompressibility of water.
 
  • Like
Likes hutchphd
  • #3
abrek said:
.. will the fact that the release of liquid occurs at a height, the water column will create resistance and less water will come out in volume?
What do you think, and why?

Note that the "special movable platform (red)" shown in the initial condition must be physically restricted by its cylinder from moving up due to the static pressure created by the 2-meter column.
 
  • Like
Likes hutchphd
  • #4
^^^^... as well as in the final condition.
 
  • #5
I think the far left hand diagram needs some explanation. Does the red (lets call it a) piston have precisely the correct mass to keep the vertical column at 2m or is it restrained from rising?; this must be specified before going any further.

When M is lowered onto the piston, it will add a force downwards on the piston and water will be pushed out of the tube. The pressure at the bottom of the tube will always be 2m's worth whilst the tube is full.

I really don't know where this is going without more information.
 

Similar threads

Replies
14
Views
7K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
270
  • Classical Physics
Replies
8
Views
3K
  • Classical Physics
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
3K
  • Introductory Physics Homework Help
Replies
16
Views
4K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Mechanical Engineering
Replies
10
Views
11K
Back
Top