Are My Calculations on Vector Functions and Fields Correct?

  • Thread starter Thread starter galipop
  • Start date Start date
  • Tags Tags
    Vector
AI Thread Summary
The calculations presented for the vector function g(x,y,z) and vector field F are mostly correct. The divergence of a vector function does not exist, confirming that divergence applies only to vector fields. The gradient of g is accurately computed, and the divergence and curl of F are also correct. It is noted that the gradient of a gradient does not exist, and the curl of the gradient of g is indeed zero. Overall, the evaluations and conclusions drawn are validated as accurate.
galipop
Messages
51
Reaction score
0
Hi Folks,

I'm just working through a few exercises relating to vector functions and vector fields.

Can you look over my working and let me know if I'm on the right track?

vector function: g(x,y,z) = x^3 + y + z^2
vector field F = (2xz , sin y , e^y)

i need to evalute the following:
1. grad g = (3x^2 , 1 , 2z)

2. div g = does not exist. From what I've seen you can't find the div of a vector function. Is this correct?

3. div F = 2z + cos y + 0

4. curl F = e^y i + (2x) j + 0k

5. grad (grad g): does not exist as this operation can't be performed twice. correct?

6. curl (grad g) = 0

7. div ( curl F ) = 0

How does the above look?

Many Thanks,

Pete
 
Physics news on Phys.org
"2. div g = does not exist. From what I've seen you can't find the div of a vector function. Is this correct?"

If you meant to write "you can't find the div of a scalar function" function, then you are right.
The divergence operator acts on a vector and produces a scalar.

"5. grad (grad g): does not exist as this operation can't be performed twice. correct?"

I would think that in the beginning course you're taking, this would be correct (not too sure, though!)

The gradient operator is customarily introduced as an operator that takes a scalar function f into the vector function \nabla{f}

If this is basically what you've been told about the gradient operator, then you have the right answer.

However, it is extremely useful in maths to also be able to calculate the "gradient" of a vector function.
This object will be a matrix.
(If this is completely unknown to you, and the book you're reading makes no references to such matrices, then you should stick with your original answer)

Otherwise, it looks good.
 


Hi Pete,

Your working looks good so far! Let's go through each part to make sure you're on the right track:

1. The gradient of g is correct. You have correctly taken the partial derivatives of each component of the vector function.

2. You are correct, the divergence of a vector function does not exist. Divergence is only defined for vector fields, not vector functions. So your answer is correct.

3. Your answer for the divergence of F is correct. You have correctly taken the partial derivatives of each component of the vector field.

4. The curl of F is also correct. You have correctly applied the curl operator to each component of the vector field.

5. You are correct again, the gradient of the gradient of g does not exist. This is because the gradient operator can only be applied once to a scalar function, not twice.

6. Your answer for the curl of the gradient of g is correct. Since the gradient of g does not exist, the curl of it will also be 0.

7. Finally, your answer for the divergence of the curl of F is also correct. You have correctly applied the divergence operator to each component of the curl of F.

Overall, your working looks good and your answers are correct. Keep up the good work! Let me know if you have any further questions.


 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top